| Server IP : 88.222.222.238 / Your IP : 216.73.217.6 Web Server : LiteSpeed System : Linux id-dci-web1986.main-hosting.eu 5.14.0-611.26.1.el9_7.x86_64 #1 SMP PREEMPT_DYNAMIC Thu Jan 29 05:24:47 EST 2026 x86_64 User : u686484674 ( 686484674) PHP Version : 8.0.30 Disable Function : system, exec, shell_exec, passthru, mysql_list_dbs, ini_alter, dl, symlink, link, chgrp, leak, popen, apache_child_terminate, virtual, mb_send_mail MySQL : OFF | cURL : ON | WGET : ON | Perl : OFF | Python : OFF | Sudo : OFF | Pkexec : OFF Directory : /proc/self/root/opt/go/pkg/mod/golang.org/x/sync@v0.10.0/semaphore/ |
Upload File : |
// Copyright 2017 The Go Authors. All rights reserved.
// Use of this source code is governed by a BSD-style
// license that can be found in the LICENSE file.
package semaphore_test
import (
"context"
"fmt"
"log"
"runtime"
"golang.org/x/sync/semaphore"
)
// Example_workerPool demonstrates how to use a semaphore to limit the number of
// goroutines working on parallel tasks.
//
// This use of a semaphore mimics a typical “worker pool” pattern, but without
// the need to explicitly shut down idle workers when the work is done.
func Example_workerPool() {
ctx := context.TODO()
var (
maxWorkers = runtime.GOMAXPROCS(0)
sem = semaphore.NewWeighted(int64(maxWorkers))
out = make([]int, 32)
)
// Compute the output using up to maxWorkers goroutines at a time.
for i := range out {
// When maxWorkers goroutines are in flight, Acquire blocks until one of the
// workers finishes.
if err := sem.Acquire(ctx, 1); err != nil {
log.Printf("Failed to acquire semaphore: %v", err)
break
}
go func(i int) {
defer sem.Release(1)
out[i] = collatzSteps(i + 1)
}(i)
}
// Acquire all of the tokens to wait for any remaining workers to finish.
//
// If you are already waiting for the workers by some other means (such as an
// errgroup.Group), you can omit this final Acquire call.
if err := sem.Acquire(ctx, int64(maxWorkers)); err != nil {
log.Printf("Failed to acquire semaphore: %v", err)
}
fmt.Println(out)
// Output:
// [0 1 7 2 5 8 16 3 19 6 14 9 9 17 17 4 12 20 20 7 7 15 15 10 23 10 111 18 18 18 106 5]
}
// collatzSteps computes the number of steps to reach 1 under the Collatz
// conjecture. (See https://en.wikipedia.org/wiki/Collatz_conjecture.)
func collatzSteps(n int) (steps int) {
if n <= 0 {
panic("nonpositive input")
}
for ; n > 1; steps++ {
if steps < 0 {
panic("too many steps")
}
if n%2 == 0 {
n /= 2
continue
}
const maxInt = int(^uint(0) >> 1)
if n > (maxInt-1)/3 {
panic("overflow")
}
n = 3*n + 1
}
return steps
}